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Amount in the beginning = Rs. 10000 Interest at the end of 1st year at rate of  is  of 10000 =  Therefore, amount at the end of 1st year will be = 10000 + 800 = 10800 Now, Interest at the end of 2nd year at rate of  is   of 10800 = Therefore,, amount at the end of 2ndyear = 10800 + 864 = 11664 Since, each subsequent term is not obtained by adding a unique number to the previous term; hence,...
Given AP series is Here,  Now, Now, we know that Now, And  And  And  Therefore, missing terms are   53,23,8,-7  AP series is 53,38,23,8,-7,-22
Given AP series is Here,  Now, we know that Now, And  And  And  Therefore, missing terms are   -2,0,2,4  AP series is -4,-2,0,2,4,6
Given AP series is Here,  Now, we know that Now, And  Therefore, missing terms are   and 8  AP series is
Given AP series is Here,  Now, Now, we know that Now, And  Therefore, missing terms are  18 and 8  AP series is 18,13,8,3
Given AP series is Here,  Now, we know that Now, Therefore, the missing term is 14
Distance travelled by the competitor in picking and dropping 1st potato  Distance travelled by the competitor in picking and dropping 2nd potato  Distance travelled by the competitor in picking and dropping 3rd potato  and so on we can clearly see that it is an AP with first term (a) = 10  and common difference(d) = 6 There are 10 potatoes in the line  Therefore, total distance travelled by...
As, the rows are going up, the no of logs are decreasing,  We can clearly see that 20, 19, 18, ..., is an AP . and here    Let suppose 200 logs are arranged in 'n' rows, Then,  Now, case (i) n = 25 But number of rows can not be in negative numbers  Therefore, we will reject the value n = 25 case (ii) n = 16 Therefore, the number of rows in which 200 logs are arranged is equal...
From the above given figure Circumference of 1st semicircle Similarly, Circumference of 2nd semicircle  Circumference of 3rd semicircle  It is clear that this is an AP with  Now, sum of length of 13 such semicircles is given by Therefore, sum of length of 13 such semicircles is 143 cm
First there are 12 classes and each class has 3 sections Since each section of class 1 will plant 1 tree, so 3 trees will be planted by 3 sections of class 1.Thus every class will plant 3 times the number of their class  Similarly, No. of trees planted by 3 sections of class 1 = 3 No. of trees planted by 3 sections of class 2 = 6 No. of trees planted by 3 sections of class 3 = 9 No. of trees...
It is given that Each price is decreased by 20 rupees,  Therefore,  d = -20 and there are total 7 prizes so n = 7 and sum of prize money is Rs 700 so  Let a be the prize money given to the 1st student Then, Therefore, the prize given to the first student is Rs 160 Now, Let  is the prize money given to the next 6 students then,    Therefore, prize money given to 1 to 7 student...
It is given that Penalty for delay of completion beyond a certain date is Rs   for the first day, Rs  for the second day, Rs  for the third day and  penalty for each succeeding day being Rs  more than for the preceding day We can clearly see that 200,250,300,..... is an AP  with  Now, the penalty for 30 days is given by the expression Therefore, the penalty for 30 days is 27750
Odd number between 0 and 50 are   1,3,5,...49 This is an AP with  There are total 25 odd number between 0 and 50 Now, we know that  Therefore,  sum of the odd numbers between and   625
First 15 multiples of 8 are   8,16,24,... This is an AP with  Now, we know that  Therefore,  sum of the first 15 multiple of 8 is 960
Positive integers divisible by 6 are  6,12,18,... This is an AP with  Now, we know that  Therefore,  sum of the first positive integers divisible by   is 4920
It is given that  the sum of the first terms of an AP is   Now, Now, first term is  Therefore, first term is 3 Similarly, Therefore, sum of first two terms is 4 Now, we know that Now, Similarly,
It is given that  We will check values of  for different values of n and so on. From the above, we can clearly see that this is an AP with the first term(a) equals to 4 and common difference (d) equals to -5 Now, we know that  Therefore, the sum of 15 terms is -465
It is given that  We will check values of  for different values of n and so on. From the above, we can clearly see that this is an AP with the first term(a) equals to 7 and common difference (d) equals to 4 Now, we know that  Therefore, the sum of 15 terms  is  525
It is given that Now, we know that  Similarly, On solving equation (i) and (ii) we will get  a = 1 and d = 2 Now, the sum of first n terms is  Therefore, the sum of n terms  is
It is given that And  Now, Now, we know that  Therefore, there are 51 terms  and their sum is 5610
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