(a) Let the whole quantity be X
Therefore, 5 % of X = 600
Thus the required whole quantity is 12000
(b) 12 % of X = Rs 1080
(c) 40 % of X = 500 km
(d) 70% of X = 14 minutes
(e) 8 % of X = 40 litre
Here per cent implies for ()
Therefore,
(a) 15% of 250
= 37.5
(b) 1 of 1 hour
= 1 of 60 minutes
(c) 20 of Rs 2500
(d) 75 of 1 kg
We know that 1kg = 1000 gm, therefore,
=0.75 kg
Given that,
Principal (PA)= Rs 7,500 at 5% p.a. (Rate of interest)
and T = 3 year
We know that,
Now, putting the values in the above equation, we get
So, Amount = PA + PI = 7,500 + 1125 = Rs 8625
Given that,
Principal (PA)= Rs 1,200 at 12% p.a. (Rate of interest)
and T = 3 year
We know that,
Now, putting the values in the above equation, we get
So, Amount = PA + PI = 1200 + 432 = Rs 1632
We have,
The ratio of calcium, carbon and oxygen in the chalk = 10 : 3: 12
Now, Sum of the ratio = 10 + 3 + 12 = 25
Therefore, the percentage of carbon in the chalk
Given that,
Original price (OP) = 3,50,000
Increased price (IP) = 3,70,000
Therefore, increase in price = OP - IP = 20,000
Thus, percentage of the increase price
(d) 1 : 2 : 5
Sum of the ratio part = 1 + 2 + 5 = 8
therefore, the percentage of the first part
the percentage of the second part
the percentage of the third part
(b) 2 : 3: 5
Sum of the ratio part = 2 + 3 + 5 = 10
Therefore, the percentage of the first part
the percentage of the second part
the percentage of the third part