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We know, a coin has two faces : Head and Tail
One can choose either Head or Tail.
Therefore, number of favourable outcome = 1
We know, Probability of any outcome

There are 6 marbles in the box numbered from 1 to 6
(i) Number of marble with number 2 on it = 1
Probability of getting a marble with number 2
(ii) Number of marble with number 5 on it = 1
Probability of getting a marble with number 5

(i) You are older today than yesterday.
-This event is certain to happen.
(ii) A tossed coin will land heads up.
- This event can happen but not certain.
(iii) A die when tossed shall land up with 8 on top.
- This event is impossible. A die can only show one of the numbers (1,2,3,4,5,6)
(iv) The next traffic light seen will be green.
- This event can happen but not certain.
(v) Tomorrow...

Table 3.1 is
The double bar graph is :
(i) From the graph,
Jammu has the largest difference between the maximum and minimum temperature bars.
Jammu is the city with the largest difference in its maximum temperature and minimum temperatures on the given date.
(ii) The city with the maximum temperature would be the hottest.
And the city with the least temperature will be the...

(i)
The double bar graph represents the number of people who like watching and participating in various sports.
We observe that,
The maximum number of people like either watching or participating in cricket.
The minimum number of people like either watching or participating in athletics.
(ii) According to the graph, the tallest bar is of cricket. Hence, cricket is the most popular...

(i) According to the graph, Maths had the maximum increase in marks.
Hence,
The child improved his performance the most in Maths.
(ii) According to the graph, S.Science had the least increase in marks.
Hence,
The child improved his performance the least in S.Science.
(iii) According to the graph, Hindi's marks went down in the second term
Hence,
The child’s performance has gone down in Hindi.

(a) The scale : 1 unit = 10 children.
(b) (i) Class fifth has the maximum number of children.
Whereas, class tenth has the minimum number of children
(ii) Number of students in class sixth = 120
Number of students in class eight = 100
Therefore, the required ratio =
Required ratio is

(i) Observing the graph,
Number of books sold in 1989 = 180
Number of books sold in 1992 = 220
Number of books sold in 1990 = 480
(ii)
475 books were sold in the year 1990
225 books were sold in the year 1992
(iii)
The years in which the total number of books sold was less than 250 are 1989 and 1992.
(iv) Around 175 books were sold in the year 1989.
By drawing a line from the top of 1989 bar...

(a)
The bar graph represents the pets owned by the students of class seven.
And, The bar of the cat is the tallest
Hence, cat is the most popular pet.
(b)
The bar of the dog is reaches the value 8
8 students have dog as pet.

(i) True.
Mode is the observation which occurs maximum number of times.
Hence, Mode will always be the one of the numbers in a data.
(ii) False.
(iii) False.
For even number of observations, the median is the mean of the and values.
(iv) Mean =
Hence, the statement is False.

Given,
Arranging in ascending order =
We know,
The mode is observation which occurs a maximum number of times.
Median is the middle observation when that data is arranged in ascending or descending order.
Now,
Clearly, occurs thrice. So, is the mode of the data.
Now, there are 9 values, so the median is the
Hence, is the median value.

Given, weights of 15 students (in kg)=
Arranging the data in ascending order =
(i) Clearly, 38 and 43 both occur thrice. So, they both are the mode of the data.
Now, there are 15 values, so the median is the
Hence, 40 is the median value.
(ii) Yes, there are two modes of the data given.

Runs scored in the match =
Arranging in ascending order =
Here, 15 occurs the maximum number of times. Hence, 15 is the mode of the data
Now,
Therefore the mean score is
Now, the median is the middle observation of the data.
There are 11 terms. Therefore the middle observation is
Therefore, 15 is the median of the data.
No, they are not the same.

Scores of 15 students are :
Arranging the data in ascending order =
We know,
Mode: The number which occurs most frequently.
Median: Median is the mid-value of the set of numbers.
Here, 20 occurs 4 times, therefore 20 is the mode of the data.
Also, the middle value is 20.
Therefore, the median of the data is 20.
Yes, the median and mode of this data are the same.

Given,
Heights of 10 girls (in cm) =
Arranging the above data in ascending order =
(i) Height of the tallest girl =
(ii) Height of the shortest girl =
(iii) Range of the data =
(iv) We know, Arithmetic mean =
Therefore, mean height of the girls is
(iv) Here, mean height =
And, are more than
Therefore, 5 girls have height more than the average height.

Given,
(i) Range = Maximum rainfall - Minimum rainfall
(ii) We know, Arithmetic mean =
Therefore, mean rainfall is
(iii) Here, mean =
Mon(0.0), Wed(2.1), Thu(0.0), Sat(5.5), Sun(1.0) are less than the mean
Therefore, on 5 days, rainfall was less than the mean.

Given,
Enrolment during 6 consecutive years =
We know, Arithmetic mean
Therefore, mean enrolment per year is

Given,
Marks obtained the students =
Arranging in ascending order =
(i) Highest marks obtained =
Lowest marks obtained =
(ii) Range of marks = Highest marks - Lowest marks
(iii) We know, Arithmetic mean
Therefore, mean marks =

Given,
We know,
(i) Therefore, A's average number of points scored per game
(ii) Number of games C played = 3
Therefore, to find the mean, we will divide by 3
Mean of C =
(iii) Although he scored 0 in a match, he played all 4 games. Therefore, we will divide by 4.
Mean of B =
(iv) Mean of A =
Mean of B =
Mean of C =
Since, A has the highest mean, A is the best performer.

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