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H Harsh Kankaria
In Roman numerals:

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H Harsh Kankaria
(a) Four multiplied by the sum of nine and two. (b) Divide the difference of eighteen and six by four. (c) Forty five divided by three times the sum of three and two.

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H Harsh Kankaria
(a)  Rounding off by general rule, 578 rounds off to 600 161 rounds off to 200, Required product =   (b)  Rounding off by the general rule, 5281 rounds off to 5000 3491 rounds off to 3500 Required product =  (c)  Rounding off by general rule, 1291 rounds off to 1300 592 rounds off to 600 Required product =  (d)   Rounding off by general rule, 9250 rounds off to 10000 29 rounds off to...

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H Harsh Kankaria
(a)  Rounding off to nearest hundreds, 439 rounds off to 400 334 rounds off to 300 4317 rounds off to 4300, Required sum =  Again, by rounding off to nearest tens, 439 rounds off to 440 334 rounds off to 330 4317 rounds off to 4320, Required sum =    (b)  Rounding off to nearest hundreds,  rounds off to  rounds off to Required difference =  Also, rounding off to nearest tens,   rounds off...

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H Harsh Kankaria
(a)       By rounding off to hundreds, 730 rounds off to 700, 998 rounds off to 1000. Required sum =    (b)  By rounding off to hundreds, 796 rounds off to 800, 314 rounds off to 300. Required difference =    (c)  By rounding off to thousands, 2904 rounds off to 13000, 2822 rounds off to 3000. Required sum =    (d)  By rounding off to nearest thousands, 28,296 rounds off to 28000, 21,496...

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H Harsh Kankaria
Given Number Approximate to Nearest Rounded Form 75847 Tens 75847 Hundreds 75847 Thousands 75847 Ten thousands

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H Harsh Kankaria
We know,   Given, Capacity of vessel = Capacity of a single glass =  Number of glasses required to fill the vessel = Hence, 180 glasses are needed to fill the vessel completely.

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H Harsh Kankaria
We know,  Given, Distance between the school and her house = The distance she covers each day =    Therefore, she will cover   in six days.

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H Harsh Kankaria
We know, Weight of each medicine box= Weight limit of the van =  The number of boxes that can be loaded in the van = Hence, 177 boxes can be loaded in the van.

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H Harsh Kankaria
We know, Given, Lenght of cloth required to stitch a shirt = Also, Now, the cloth required for one shirt = Number of shirts that can be stitched out = Therefore, 18 shirts can be made from the given cloth. And,  cloth will remain unused.

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H Harsh Kankaria
Given, The student multiplied instead of . Wrong answer =  Correct answer =   The difference in the answers = Hence, his answer was greater than the correct answer by

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H Harsh Kankaria
Total money merchant has = Cost of one radio set =  Cost of 40 radio sets =  Money left with the merchant = Therefore, money left with her after purchase =

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H Harsh Kankaria
Given, Screws produced by machine in one day = We know, there are 31 days in January   Screws produced in 31 days = Therefore, screws produced in January 2006 =

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H Harsh Kankaria
Given, digits: 6, 2, 7, 4 and 3  Since, the digits have to be used only once, arrange them in ascending and descending order to get the minimum and maximum number. Greatest number = Smallest number =  The difference between the greatest and the least number

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H Harsh Kankaria
Given, Worth of books sold in the first week = Worth of books sold in the second week = Total sale in the two weeks = Clearly, sales in the second week is greater than the first year by

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H Harsh Kankaria
Given, Number of votes registered by the successful candidate = 5, 77,500 votes Number of votes registered by the rival candidate = 3, 48,700 votes The margin                   Therefore, the successful candidate won the election by a margin of votes.

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H Harsh Kankaria
The number of runs scored by Shekhar so far = 6980 The number of runs shekhar wishes to score = 10,000  The number of runs required = Therefore, Shekhar requires .

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H Harsh Kankaria
Given, Tickets sold on the first day of exhibition = 1094 Tickets sold on the second day = 1812 Tickets sold on the third day  = 2050 Tickets sold on the last day = 2751 Total number of tickets sold =  Total number of tickets sold =

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H Harsh Kankaria
(i) Total distance from A to D = AB + BC + CD (ii) Total distance between D to G = DE + EF + FG   (iii) Required distance = AD + DG + GA (iv) The difference of distances from C to D and D to E

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H Harsh Kankaria
Number of medicine tablets =  Weight of each medicine tablet =  Therefore, total weight =
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