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Area  of shaded portion = Area of the whole rectangle ( ABCD ) - Area of two triangles ( AFE and BCE) Area of the rectangle with length 18 cm and width 10 cm is Area of triangle AFE with base 10 cm and height 6 cm is Area of triangle BCE with base 8 cm and height 10 cm is Now, Area  of the shaded portion is 
We know that circumference of the circle is =  Circumference of the flower bed with radius 2 m is Therefore, the circumference of the flower bed with radius 2 m is  
Area of the lawn excluding the area of the flower bed = Area of rectangular lawn - Area of flower bed                                                                                        =  Therefore, area of the lawn excluding the area of the flower bed is 
We know that area of circle is =  Area of flower bed with radius 2 m is Therefore, area of flower bed with radius 2 m is 
We know that area rectangle is = Area of rectangular land with length 10 m and width 5 m is  Therefore, area of rectangular land with length 10 m and width 5 m is 
It is given that the radius of the circle is 4 cm We know that circumference of circle =  And perimeter of the square is  Length of cord left is  Therefore, Length of cord left is  
It is given that the width of each road is  and the length of rectangular park is  and breadth is  Now, We know that area of rectangle is =  Area of the total park is                     -(i) Area of road parallel to the width of the park ( ABCD ) is                            -(ii) Area of road parallel to the length of park ( PQRS )  is                           -(iii) The...
It is given that the width of each road is  and length of rectangular park is  and breadth is  Now, We know that area of rectangle is =  Area of total park is                     -(i) Area of road parallell to width of the park ( ABCD ) is                            -(ii) Area of road parallel to length of park ( PQRS )  is                           -(iii) The common area of both...
It is given that width of each road is  and the length of rectangular park is  and breadth is  Now, We know that area of rectangle is =  Area of total park is                     -(i) Area of road parallell to width of the park ( ABCD ) is                            -(ii) Area of road parallel to length of park ( PQRS )  is                           -(iii) The common area of...
It is given that room  is long and  wide. It is clear that it is rectangular shaped with   We know that the area of the rectangle is                     -(i) Now, when verandah of width   is constructed all along outside the room then length and breadth of the room  is Area of the room after verandah of width   is constructed                               -(ii) Area of verandah is...
It is given that room  is long and  wide. It is clear that it is rectangular shaped with   We know that the area of the rectangle is                     -(i) Now, when verandah of width   is constructed all along outside the room then length and breadth of the room  is Area of the room after verandah of width   is constructed                               -(ii) Area of verandah is...
It is given that cardboard is  long and wide such that there is a margin of along each of its sides It is clear that it is rectangular shaped with  We know that the area of the rectangle is                     -(i) Now, the length and breadth of cardboard without margin is Area of cardboard without margin is                                -(ii) Area of margin is (i) -...
It is given that park is   long and   broad It is clear that it is rectangular shaped with  We know that area of rectangle is                     -(i) Now, length and breadth of outer rectangle is Area of outer rectangle is                                -(ii) Area of path is (ii) - (i) Therefore,  area of path is 
It is given that the garden is long and broad It is clear that it is rectangular shaped with  We know that the area of the rectangle is                     -(i) Now, length and breadth of the outer rectangle is Area of the outer rectangle is                                -(ii) Area of the path is (ii) - (i) Therefore, the area of the path is   
It is given that minute hand of a circular clock is long  i.e. ( r = 15 cm) Now, we know that one hour means a complete circle of minute hand Now, Circumference of circle =  Therefore,  distance cover by minute hand in one hour is  94.2 cm
It is given that radius of wheel is  Now, we know that  Circumference of circle =  Now, number of rotation done by wheel to go 352 m  is  Therefore,  number of rotation done by wheel to go 352 m is  200
We know that  Circumference of circle =  Now, the circumference of the inner circle  with radius (r) =  is  And the circumference of the outer circle  with radius (r ') = 19 m is Therefore, the circumference of inner and outer circles are   respectively
It is given that the radius of the sprinkler is  Now, we know that Area of the circle (A) =  Area cover by sprinkle is And the area of the flower garden is                           Therefore,  YES  sprinkler water the entire garden
It is given that the diameter of the flower bed is  Therefore,  Now, we know that Area of the circle (A) =                               -(i) Now, Area of outer circle with radius(r ') = 33 + 4 = 37 cm is                                 -(ii)                                        Area of the path is equation (ii) - (i) Therefore, the area of the path is  
It is given that circumference of circle is  Now, we know that Circumference of circle is =  Now, Area of circle (A) =                                         Therefore, radius and  area of the circle  are   respectively 
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