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Area of the parallelogram is the product of base and height
Area of the parallelogram is the product of base and height
The arc length of the circle is slightly greater than the side length of the inner square. Therefore circumference of the inner circle is greater than the inner square
The outer square has a larger perimeter. Since each side of the inner square forms a triangle. The length of the third side of a triangle is less than the sum of the other two lengths.
The conversion is done as follows
1m = 100cm Therefor
ha represents hectare 1 ha is 10000 m2 therefor
1 cm = 10 mm therefor
Area of parallelogram = the product of base and height
The total area of rectangle  i) The first rectangle is divided into 6 equal parts. So the area of each part will be one-sixth of the total area  ii) The rectangle is divided into 4 equal parts, area of each part= one-forth area of rectangle= 6 cm2 iii) and (iv) are divided into two equal parts. Area of each part will be one half the total area of rectangle= 12  cm2 v) Area of rectangle is...
Area of a rectangle with length = 20cm, breadth = 5 cm is 100cm2 and perimeter is 50 cm. A rectangle with sides 50 cm and 2 cm ha area = 100cm2  but perimeter is 104 cm
A square of side 1m has perimeter 4 m and area 1 m2. When all sides are increased by 1m then perimeter =8m and area= 4 m2. Similarly if we increase the length from 6m to 9m and breadth from 3m to 6m  of a rectangular the perimeter and area will increase
plastic sheet need to cover is the area of the rectangular swimming pool
Distance covered by taking round a triangular park is equal to the circumference of the triangular park
The length of the wire to fence a flower bed is the circumference of the flower bed
The space of the board includes whole area of the board
Is is given that side of square garden is  We know that area of square is =                     -(i) Now, area of square garden without 1 m boarder is                               -(ii) Area of path is (i) - (ii) Therefore,  area of path is   Now,  cost of planting grass in the remaining portion of the garden at the rate of  is  Therefore,  cost of planting grass in the...
Is is given that side of square garden is  We know that area of square is =                     -(i) Now, area of square garden without 1 m boarder is                               -(ii) Area of path is (i) - (ii) Therefore,  area of path is
Area  of  quadrilateral ABCD = Area of triangle ABC + Area of tringle ADC   Area of triangle ABC with base 22 cm and height 3 cm is Area of triangle ADX with base 22 cm and height 3 cm is Therefore, the area of quadrilateral ABCD is =
Area  of shaded portion = Area of the whole square ( PQRS ) - Area of three triangles ( PTQ , STU and QUR ) Area of the square with side 20cm is Area of triangle PTQ with base 10 cm and height 20 cm is Area of triangle STU with base 10 cm and height 10 cm is Area of triangle QUR with base 20 cm and height 10 cm is Now, Area  of the shaded portion is
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