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The steps of constructions are:
1. Draw a ray OA
2. Taking O as the centre and convenient radius, mark an arc, which intersects OA at X.
3. Taking X as the centre and the same radius, cut the previous arc at Y. Taking Y as the centre and the same radius, draw another arc intersecting the same arc at Z.
4. Taking Y and Z as centres and the same radius, draw two arcs intersecting each other at...

Follow the steps to draw the perpendicular bisector of a line XY.
a) PX= PY
b)MX=MY

The steps of constructions are:
(i) Draw a line segment = 10.3 cm
(ii) Taking X and Y as centres and radius more than half of AB, draw two arcs which intersect each other at C and D.
(iii) Join CD. Then CD is the required perpendicular bisector of .
Now:
(a) Take any point P on the bisector drawn. With the help of divider, we can check that =.
(b) If M is the mid-point of , then ???????

The steps of constructions are:
(a) Draw an angle of 40 degrees with the help of protractor, naming ∠ AOB.
(b) Draw a line PQ.
(c) Take any point M on PQ.
(d) Place the compasses at O and draw an arc to cut the rays of ∠AOB at L and N.
(e) Use the same compasses setting to draw an arc O as the centre, cutting MQ at X.
(f) Set your compasses to length LN with the same radius.
(g) Place the...

The steps of constructions are:
(a) Draw an angle 70 degrees with a protractor, i.e., ∠POQ = 70 degrees
(b) Draw a ray AB.
(c) Place the compasses at O and draw an arc to cut the rays of ∠POQ at L and M.
(d) Use the same compasses, setting to draw an arc with A as the centre, cutting AB at X.
(e) Set your compasses setting to the length LM with the same radius.
(f) Place the compasses pointer...

The steps of constructions are:
(a) Draw a line PQ and take a point O on it.
(b) Taking O as the centre and convenient radius, mark an arc, which intersects PQ at A and B.
(c) Taking A and B as centres and radius more than half of AB, draw two arcs intersecting each other at R.
(d) Join OR. Thus, ∠QOR = ∠POQ = 90 .
(e) Draw OD the bisector of ∠POR. Thus, ∠QOD is the required angle of 135.
(f)...

The steps of constructions are:
1. Draw a ray OA
2. Taking O as the centre and convenient radius, mark an arc, which intersects OA at X.
3. Taking X as a centre and the same radius, cut the previous arc at Y. Taking Y as the centre and the same radius, draw another arc intersecting the same arc at Z.
4. Taking Y and Z as centres and the same radius, draw two arcs intersecting each other at S....

The steps of constructions are:
1. Draw a line PQ and take a point O on it.
2. Taking O as the centre and convenient radius, mark an arc, which intersects PQ at A and B.
3. Taking A and B as centres and radius more than half of AB, draw two arcs intersecting each other at R. Join OR. Thus, ∠QOR = ∠POR = 90°.
4. Draw OD the bisector of ∠POR. Thus, ∠QOD is required angle of 135°

The steps of constructions are:
1. Draw a ray OA
2. Taking O as the centre and convenient radius, mark an arc, which intersects OA at X.
3. Taking X as the centre and the same radius, cut the previous arc at Y. Taking Y as the centre and the same radius, draw another arc intersecting the same arc at Z.
4. Taking Y and Z as centres and the same radius, draw two arcs intersecting each other at...

The steps of constructions are:
1. Draw a ray OA
2. Taking O as the centre and convenient radius, mark an arc, which intersects OA at P.
3. Taking P as the centre and same radius, cut previous arc at Q. Taking Q as the centre and the same radius cut the arc at S. Join OS. Thus, ∠AOS is the required angle of 120°.

The steps of constructions are:
1. Draw a ray OA.
2. Taking O as the centre and convenient radius, mark an arc, which intersects OA at P.
3. Taking P as the centre and the same radius, cut the previous arc at Q. Join OQ. Thus, ∠BOA is the required angle of 60°.
4. Put the pointer on P and mark an arc.
5. Put the pointer on Q and with the same radius, cut the previous arc at C. Thus, ∠COA is...

The steps of constructions are:
1. Draw a ray OA
2. Taking O as the centre and convenient radius, mark an arc, which intersects OA at P.
3. Taking P as the centre and the same radius, cut the previous arc at Q. Join OQ. Thus,∠BOA is the required angle of 60°

The steps of constructions are:
(a) Draw a ray OA.
(b) At O, with the help of a protractor, construct ∠AOB = 153 degrees.
(c) Draw OC as the bisector of ∠AOB.
(d) Again, draw OD as bisector of ∠AOC.
(e) Again, draw OE as bisector of,∠BOC.
(f) Thus, OC, OD, and OE divide ∠AOB into four equal parts.

The steps of construction:
(a) Draw a line PQ and take a point O on it.
(b) Taking O as the centre and convenient radius, draw an arc that intersects PQ at A and B.
(c) Taking A and B as centres and radius more than half of AB, draw two arcs which intersect each other at C.
(d) Join OC. Thus, ∠COQ is the required right angle.
(e) Taking B and E as centre and radius more than half of BE, draw...

The steps of constructions are:
1. Draw a line OA.
2. Using protractor and centre 'O draw an angle AOB =147°.
3. Now taking 'O' as the centre and any radius draws an arc that intersects 'OA' and 'OB' at p and q.
4. Now take p and q as centres and radius more than half of PQ, draw arcs.
5. Both the arcs intersect at 'R'
6. Join 'OR' and produce it.
7. 'OR' is the required bisector of...

Here, we will draw using a protractor.
We follow these steps:
1. Draw a ray OA.
2. Place the centre of the protractor on point O, and coincide line OA and Protractor line
3. Mark point B on 75 degrees.
4. Join OB
Therefore
Now, we need to find its line of symmetry
that is, we need to find its bisector.
We follow these steps
1. Mark points C and D where the arc intersects OA and OB
2. Now,...

The steps of constructions are:
(i) Draw any angle with vertex O.
(ii) Take a point A on one of its arms and B on another such that
(iii) Draw perpendicular bisector of and .
(iv) Let them meet at P. Join PA and PB.
With the help of divider, we obtained that

The steps of constructions are:
(i) Draw the circle with O and radius 4 cm.
(ii) Draw any two chords and in this circle.
(iii) Taking A and B as centres and radius more than half AB, draw two arcs which intersect each other at E and F.
(iv) Join EF. Thus EF is the perpendicular bisector of chord .
(v) Similarly draw GH the perpendicular bisector of chord .
These two perpendicular bisectors...

The steps of constructions are:
(i) Draw a circle with centre C and radius 3.4 cm.
(ii) Draw its diameter
(iii) Taking A and B as centres and radius more than half of it, draw two arcs which intersect each other at P and Q.
(iv) Join PQ. Then PQ is the perpendicular bisector of
We observe that this perpendicular bisector of passes through the centre C of the circle.

The steps of constructions are:
(i) Draw a circle with centre C and radius 3.4 cm.
(ii) Draw any chord .
(iii) Taking A and B as centres and radius more than half of , draw two arcs which cut each other at P and Q.
(iv) Join PQ. Then PQ is the perpendicular bisector of .
This perpendicular bisector of passes through the centre C of the circle.

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