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(i) The number of students in a class. (ii) The number of books in a library. (iii) Toys sold on a particular day at a shop. (iv) People who voted for a particular candidate. (v) Runs scored by a batsman on each ball in a particular evening. All of the data in Q.1 is primary data.
Five examples of data that we can collect in our daily life are (i) Number of students in a class. (ii) The number of books in a library. (iii) Toys sold on a particular day at a shop. (iv) People who voted for a particular candidate. (v) Runs scored by a batsman on each ball in a particular evening.
Production yield (Upper-Class Limit) Cumulative Frequency More than or equal to 50 100 More than or equal to 55 98 More than or equal to 60 90 More than or equal to 65 78 More than or equal to 70 54 More than or equal to 75 16 Now, Taking lower class limit on the x-axis and their respective frequencies on the y-axis,
Taking upper-class interval on the x-axis and their respective frequencies on the y-axis, Marking a point on the curve whose ordinate is 17.5 gives an x-ordinate= 46.5. Hence, the Median of the data is 46.5 Now, Weight (Class) Frequency Cumulative Frequency >38 0 0 38-40 3 3 40-42 2 5 42-44 4 9 44-46 5 14 46-48 14 28 48-50 4 32 50-52 3 35  Median class = 46-48;...
Daily Income (Upper Class Limit) Cumulative Frequency Less than 120 12 Less than 140 26 Less than 160 34 Less than 180 40 Less than 200 50 Now, Taking upper class interval on x-axis and their respective frequencies on y-axis,
Class Number of students  Cumulative Frequency 40-45 2 2 45-50 3 5 50-55 8 13 55-60 6 19 60-65 6 25 65-70 3 28 70-75 2 30 MEDIAN:  Median class = 55-60; Lower limit, l = 55;  Cumulative frequency of preceding class, c.f. = 13; f = 6; h = 5 Thus, median weight of the student is 56.67 kg
Class Number of surnames  Cumulative Frequency Class mark 1-4 6 6 2.5 15 4-7 30 36 5.5 165 7-10 40 76 8.5 340 10-13 16 92 11.5 184 13-16 4 96 14.5 51 16-19 4 100 17.5 70     = 100   = 825 MEDIAN:  Median class = 7-10; Lower limit, l = 7;  Cumulative frequency of preceding class, c.f. = 36; f = 40; h = 3 Thus, the median of the data is 8.05 MODE: The...
Class Frequency   Cumulative Frequency 1500-2000 14 14 2000-2500 56 70 2500-3000 60 130 3000-3500 86 216 3500-4000 74 290 4000-4500 62 352 4500-5000 48 400 Therefore, Median class = 3000-3500 Lower limit, l = 3000; Class height, h = 500 Frequency corresponding to median class, f = 86 Cumulative frequency of the class preceding the median class, c.f. =...
The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. Class Frequency   Cumulative Frequency 117.5-126.5 3 3 126.5-135.5 5 8 135.5-144.5 9 17 144.5-153.5 12 29 153.5-162.5 5 34 162.5-171.5 4 38 171.5-180.5 2 40 Therefore, Median class = 144.5-153.5 Lower limit, l = 144.5; Class height, h =...
Class Frequency   Cumulative Frequency 15-20 2 2 20-25 4 6 25-30 18 24 30-35 21 45 35-40 33 78 40-45 11 89 45-50 3 92 50-55 6 98 55-60 2 100 Therefore, Median class = 35-45 Frequency corresponding to median class, f = 21 Cumulative frequency of the class preceding the median class, c.f. = 24 Lower limit, l = 35; Class height, h = 10 Thus, median age is 35.75 years.
Class Number of consumers  Cumulative Frequency 0-10 5 5 10-20 x 5+x 20-30 20 25+x 30-40 15 40+x 40-50 y 40+x+y 50-60 5 45+x+y   = 60   Now, Given median = 28.5 which lies in the class 20-30 Therefore, Median class = 20-30 Frequency corresponding to median class, f = 20 Cumulative frequency of the class preceding the median class, c.f. = 5 + x Lower limit, l...
Let the assumed mean be a = 130 and h = 20 Class Number of consumers  Cumulative Frequency Class mark 65-85 4 4 70 -60 -3 -12 85-105 5 9 90 -40 -2 -10 105-125 13 22 110 -20 -1 -13 125-145 20 42 130 0 0 0 145-165 14 56 150 20 1 14 165-185 8 64 170 40 2 16 185-205 4 68 190 60 3 12     = 68       = 7 MEDIAN:  Median class = 125-145; Cumulative Frequency...
The class having maximum frequency is the modal class. The maximum frequency is 20 and hence the modal class = 40-50 Lower limit (l) of modal class = 40, class size (h) = 10 Frequency ( ) of the modal class = 20 frequency ( ) of class preceding the modal class = 12, frequency ( ) of class succeeding the modal class = 11 Thus, Mode of the data is 44.70
The class having maximum frequency is the modal class. The maximum frequency is 18 and hence the modal class = 4000-5000 Lower limit (l) of modal class = 4000, class size (h) = 1000 Frequency ( ) of the modal class = 18 frequency ( ) of class preceding the modal class = 4, frequency ( ) of class succeeding the modal class = 9 Thus, Mode of the data is 4608.70
The class having maximum frequency is the modal class. The maximum frequency is 10 and hence the modal class = 30-35 Lower limit (l) of modal class = 30, class size (h) = 5 Frequency ( ) of the modal class = 10 frequency ( ) of class preceding the modal class = 9, frequency ( ) of class succeeding the modal class = 3 Thus, Mode of the data is 30.625 Now, Let the assumed mean be a =...
The class having maximum frequency is the modal class. The maximum frequency is 40 and hence the modal class = 1500-2000 Lower limit (l) of modal class = 1500, class size (h) = 500 Frequency ( ) of the modal class = 40 frequency ( ) of class preceding the modal class = 24, frequency ( ) of class succeeding the modal class = 33. Thus, Mode of the data is Rs. 1847.82 Now, Let the assumed...
The class having maximum frequency is the modal class. The maximum frequency is 61 and hence the modal class = 60-80 Lower limit (l) of modal class = 60, class size (h) = 20 Frequency ( ) of the modal class = 61 frequency ( ) of class preceding the modal class = 52, frequency ( ) of class succeeding the modal class = 38. Thus, the modal lifetime of 225 electrical components is 65.62 hours
The class having maximum frequency is the modal class. The maximum frequency is 23 and hence the modal class = 35-45 Lower limit (l) of modal class = 35, class size (h) = 10  Frequency ( ) of the modal class = 23, frequency ( ) of class preceding the modal class = 21, frequency ( ) of class succeeding the modal class = 14. Now, Age   Number of patients  Class...
Let the assumed mean be a = 75 and h = 10 Literacy rates   Number of cities  Class mark 45-55 3 50 -20 -2 -6 55-65 10 60 -10 -1 -10 65-75 11 70 0 0 0 75-85 8 80 10 1 8 85-95 3 90 20 2 6   = 35       = -2 Mean,    Therefore, the mean mean literacy rate is 69.43%
Number of days Number of Students  Class mark 0-6 11 3 33 6-10 10 8 80 10-14 7 12 84 14-20 4 17 68 20-28 4 24 96 28-38 3 33 99 38-40 1 39 39             =40   =499 Mean,  Therefore, the mean number of days a student was absent is 12.48 days.
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