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Room Temperature, T1 =  36o C = 309 K The temperature which has to be maintained inside the fridge, T2 = 9o C = 282 K Coefficient of performance is E
The work done by the gas as it goes from state D to E to F is equal to the area of triangle DEF DF is change in pressure = 300 N m-2 FE is change in Volume = 3 m3 Work done is therefore 450 J.
Rate at which heat is supplied  Rate at which work is done  Rate of change of internal energy is  The internal energy of the system is increasing at a rate of 25 J s-1
Output =  Input =  Efficiency is  The efficiency of the engine is 0.15. The percentage efficiency of the engine is 15%. Heat wasted per minute = Heat produced per minute - useful work done per minute
As the entire system is thermally insulated and as free expansion will be taking place the temperature of the gas remains the same. Therefore PV is constant. Initial Pressure P1 = 1 atm Initial Volume, V1 = V Final Volume, V2 = 2V Final Pressure P2 will be The final pressure of the gas in A and B is 0.5 atm. b) Since the temperature of the gas does not change its internal energy would also...
In the first case, the process is adiabatic i.e.  22.3 J work is done on the system i.e.  Since in the latter process as well the initial and final states are the same as those in the former process  will remain the same for the latter case. In the latter case net heat absorbed by the system is 9.35 cal The network done by the system in the latter case is 17.0 J
As the walls of the cylinder and the piston is insulated the process will be adiabatic. i.e.  would be constant. Hydrogen is a diatomic gas and therefore  Let the initial and final pressure be P1 and P2 respectively. Let the initial and final volume be T1 and T2 respectively. The pressure thus increases by a factor 2.639
The climate of a harbour town is more temperate than that of a town in a desert at the same latitude because of the formation of sea breezes.
As the car is driven the air inside the tyre heats due to frictional forces. Thus the temperature of the air inside the tyre increases and this, in turn, increases the pressure inside the tyre.
The coolant should have high specific heat so that it can absorb large amounts of heat without itself getting too hot and its temperature lies in the permissible region. Higher is the specific heat more will be the heat absorbed by the same amount of the material for a given increase in temperature.
As we know the heat will flow from the hotter body to the colder body till their temperatures become equal. That temperature will be equal to the mean of the initial temperatures of the bodies only if the two thermal capacities of the two bodies are equal.
Mass of nitrogen,  Molar Mass of nitrogen, MN = 28 g Number of moles is n As nitrogen is a diatomic gas it's molar specific heat at constant pressure CP is as follows Rise in temperature,  Amount of heat Q that must be supplied is
The volumetric flow of water is Density of water = 1000 g/litre The mass flow rate of water is  Specific heat of water, c = 4.2 J g-1 oC-1 The rise in temperature is  Rate of energy consumption will be The heat of combustion of fuel  Rate of consumption of fuel is
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