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12 cards numbered 1 to 12 (one number on one card), are placed in a box and mixed up thoroughly. Then a card is drawn at random from the box. If it is known that the number on the drawn card is greater than 5, find the probability that the card bears an odd number.

 

 

 

 
 
 
 
 

Answers (1)

Let A : the card beans odd number and
      B: number on the card be is greater than 5
clearly A= \left \{ 1,3,5,7,9,11 \right \}
           B= \left \{ 6,7,8,9,10,11,12 \right \}
A\cap B= \left \{ 7,9,11 \right \}
\therefore p\left ( \frac{A}{B} \right )= \frac{p\left ( A\cap B \right )}{p\left ( B \right )}= \frac{\frac{3}{12}}{\frac{7}{12}}\Rightarrow \frac{3}{7} 

Posted by

Ravindra Pindel

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