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A body is projected so that is has maxmum range R .then what is the maxmum height reached during the flight?

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       R=\frac{u^{2}\sin 2\Theta }{g}

So to get the maximum range the angle must be equal to 45^0
 

-H= \frac{U^{2}\sin ^{2}\Theta }{2g}

So using \theta =45^0


H=\frac{R}{4}

Posted by

avinash.dongre

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