# A body of mass 4 kg is thrown up with a speed of 30m/s calculate KINETIC ENERGY of body and POTENTIAL ENERGY at top

$\begin{array}{l} m=4 \mathrm{kg} \quad \mathrm{v}=30 \mathrm{m} / \mathrm{s} \\ \mathrm{KE}=\frac{1}{2} \mathrm{mv}^{2} =\frac{1}{2} \times 4 \times\left(30^{2}\right)=1800 \mathrm{J} \end{array}$

When body reaches the highest point, its entire kinetic energy gets converted into potential energy.

So, P.E. at top=1800J

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