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A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

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\\ \text{A's 1 day's work} =\frac{1}{15}$ \\ B's 1 day's work $=\frac{1}{20}$ \\ $(\mathrm{A}+\mathrm{B})^{\prime} \mathrm{s} 1$ day's work \\ $=\left(\frac{1}{15}+\frac{1}{20}\right)=\frac{7}{60}$ \\ $(\mathrm{A}+\mathrm{B})$ 's 4 day's work $=\left(\frac{7}{60} \times 4\right)=\frac{7}{15}$ \\ Therefore, Remaining work $=\left(1-\frac{7}{15}\right)=\frac{8}{15}.

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Deependra Verma

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