Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • A linear harmonic oscillator of force constant 2×10^6 N/m and amplitude (0.01 m) has a total mechanical energy of (160 J). Its (a) maximum potential energy is 100 J (b) maximum kinetic energy is 160 J (c) minimum potential energy is 100 J (d) maximum kin

A linear harmonic oscillator of force constant 2×10^6 N/m and amplitude (0.01 m) has a total mechanical energy of (160 J). Its (a) maximum potential energy is 100 J (b) maximum kinetic energy is 160 J (c) minimum potential energy is 100 J (d) maximum kinetic energy is 100 J

Answers (1)

In SHM, P.E. is minimum at mean position and K.E. is maximum at mean position. But the total meachanical energy in SHM is constant. Therefore, at mean position.,
total mechanical energy == max. K.E. + minimum P.E.

 

160=100+ minimum P.E.
So, minimum P.E. =160−100=60J

Posted by

shubham.krishnan

View full answer

Similar Questions

Latest Question