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A liquid of density ? is filled up to a height h in a cubical container of side length a. Torque, due to hydrostatic force acting on a wall, about the bottom edge of the wall is

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Pressure = P = ρgy.

Force =  \frac{1}{2} \rho g h^2

\tau=\text { Force } \times \text { distance }=\left(\frac{1}{2} \rho g h^2 a\right) \cdot \frac{h}{3}=\frac{1}{6} \rho g a h^3

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Divya Sharma

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