Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • A problem is given to three students whose probabilities of solving it are and <img alt="\frac{1}{6}" src="https://learn

A problem is given to three students whose probabilities of solving it are \frac{1}{3},\frac{1}{4} and \frac{1}{6}  respectively. If the events of solving the problem are independent, find the probability that at least one of them solves it.

 

 

Answers (1)

E_{1}:$ Student 1 is able to solve the problem

P(E_{1}) = \frac{1}{3}

E_{2}:$ Student 2 is able to solve the problem

P(E_{2}) = \frac{1}{4}

E_{3}:$ Student 3 is able to solve the problem

P(E_{3}) = \frac{1}{6}

\\ P($Atlest one will able to solve $) =1- P(E'_{1}) \cdot P(E'_{2}) \cdot P(E'_{3})\\\\ = 1- \frac{2}{3} \times \frac{3}{4} \times \frac{5}{6} \\\\= \frac{72-30}{72} \\\\ = \frac{7}{12}

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 Board Exam 2026 LIVE: 12th economics paper ends; pattern, timings, answer key updates
anam-khan

CBSE Results 2026: Board warns teachers of legal action for sharing 'misleading' information on evaluation
anam-khan

CBSE 12th Hindi Analysis 2026: Paper ‘easy, balanced’ with direct questions, say experts

Latest Question