A train accelerates from 36km/hr to 54km/hr in 10 sec. Find a) Accelaration b) The distance travelled by a car​

Answers (1)

Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s
Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s
Time t = 10 s
Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Distance travelled  S = ut + ½ at2
                                     = 10 x 10 + ½ x 0.5 x 10 x 10     m
                                     = 100 + 25 = 125 m

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