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  • A train accelerates from 36km/hr to 54km/hr in 10 sec. Find a) Accelaration b) The distance travelled by a car​

A train accelerates from 36km/hr to 54km/hr in 10 sec. Find a) Accelaration b) The distance travelled by a car​

Answers (3)

Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s
Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s
Time t = 10 s
Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Distance travelled  S = ut + ½ at2
                                     = 10 x 10 + ½ x 0.5 x 10 x 10     m
                                     = 100 + 25 = 125 m

Posted by

shubham.krishnan

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125 m

 

 

 

 

 

Posted by

shubhangi

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Here, initial speed, u=36km-¹=36×5/18ms-¹=10ms-¹

Final speed, v= 54×15/8ms-¹=15ms-¹

Time, t=10s.

(a) now using the formula a=v-u/t, we get

a=(15-10) ms-¹=-5ms-¹/10s

=0.5ms-²

(b) now using the relation 

S=ut+½at²

Substituting the given values

s=10ms-¹×10s+½×0.5ms-²×100s²

=100m+25m=125

Posted by

Official fairy

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