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An aircraft is vertically above a point which is 10 km west and 15 km north from a control tower. If the aircraft is 4000 m above the ground, how far is it from the control tower.

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It is a question of 3D geometry 

x=10Km;y=15Km;z=4000m=4Km

Distance^2=x^2+y^2+z^2

Distance^2=10^2+15^2+4^2

Distance=sqrt100+225+16=sqrt341=18.466; Km

Posted by

Deependra Verma

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