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An iron cube of density 7.6 g/cubic cm has a side of 5cm. Calculate the net force acting on the metal cube in alcohol of density 0.8g/cubic cm, take g=10

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\\\\Net \ force\ F=\rho_{iron} Vg-\rho_{liquid}Vg\\\\F=vg(\rho_{iron}-\rho_{liquid})=25\times9.8(7.6-0.8)=1666N

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Safeer PP

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