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  • An object at a distance of +15cm is slowly move towards the pole of a convex mirror, the image will be a. shortened and real b. enlarged and real c. enlarged and virtual d. diminished and virtual​

An object at a distance of u is slowly move towards the pole of a convex mirror, the image will be a. shortened and real b. enlarged and real c. enlarged and virtual d. diminished and virtual​

Answers (1)

\\ \text{let u=-u and f be focal length} \\ \begin{array}{l} \frac{1}{v}+\frac{1}{u}=\frac{1}{f} \\ \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ v=\frac{f u}{f+u} \end{array} \\ |$magnification$|=|-\frac{v}{u} |=\frac{f}{u+f}$ i.e, as object moves nearer to pole u decreases hence the magnification increases

So option c is correct.

Posted by

shubham.krishnan

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