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An unbiased coin is tossed 4 times. Find the probability of getting at least one head.

Answers (1)

$$ P(head ) $ = \frac{1}{2}$

$$ P(tail) $ = \frac{1}{2}$

$$ P(No head or all four tail ) $ = \left(\frac{1}{2}\right)^{4}=\frac{1}{16}$

$$P(Atleast one head )$ = 1-\frac{1}{16}= \frac{15}{16}$

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