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Explain solution RD Sharma class 12 chapter Differentials Errors and Approximations exercise 13.1 question 16 maths

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Answer: 0.03 x^{3} m^{3}

Hint: Here we use the formula of a cube of side x is given by v=x^{3}

Given: 1% increasing

Solution:\left(\frac{d v}{d r}\right) \Delta x

\begin{aligned} &=3 x^{2} \Delta x \\\\ &=3 x^{2} \times 0.01 x \\\\ &=0.03 x^{3} \end{aligned}

⇒ hence the approximate change in the volume of the cube is 0.03 x^{3} m^{3}

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