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Provide solution for RD Sharma maths class 12 chapter Differentials Errors and Approximations exercise  13.1 question 14

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Answer: 2% decrease

Hint: Here, we use the formula of surface area of cube

        s=6 x^{2}

Given: \Delta x=1 \% \text { decrease }


\begin{aligned} &\Delta x=(-0.01) x \\\\ &d s=\frac{d s}{d x} \times \Delta x=6 \times 2 \Delta x \end{aligned}

      \begin{aligned} &=6 \times 2 x \times(-0.01 x) \\\\ &=-0.12 x^{2} \end{aligned}

Therefore -0.12x^{2} is the approximate change in surface area of cube

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