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  • Provide solution for RD Sharma maths class 12 chapter Differentials Errors and Approximations exercise 13.1 question 10

Provide solution for RD Sharma maths class 12 chapter Differentials Errors and Approximations exercise  13.1 question 10

Answers (1)

Answer: 28.21

Hint: Here we use this below formula

f(x+\Delta x)-f(x)=\Delta y

Given:f(2.01), f(x)=4 x^{2}+5 x+2

Solution: f 2.01=f(x+\Delta x)

=4(x+\Delta x)^{2}+5(x+\Delta x)+2

\begin{aligned} &\Delta y=f(x+\Delta x)-f(x) \\\\ &\Rightarrow f(x)+f(x) x \Delta x \\\\ &f(2.01)=\left(4 x^{2}+5 x+2\right)+(8 x+5) \Delta x \end{aligned}

\begin{aligned} &=\left(4(2)^{2}+5((2)+2)[8(2)+5](0.01)\right. \\\\ &=(16+10+2)+(16+5)(0.01) \\\\ &=28+0.21 \\\\ &=28.21 \end{aligned}

Hence, the approximate value of f(2.01) \text { is } 28.21

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