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  • find the coordinates of the centre of the circle which bisects the circumferences of the circles x^2+y^2=1, x^2+y^2+2x?3=0 and x^2+y^2+2y?3=0.

find the coordinates of the centre of the circle which bisects the circumferences of the circles x^2+y^2=1, x^2+y^2+2x?3=0 and x^2+y^2+2y?3=0.

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x^2+y^2=1...(i)\*x^2+y^2+2x-3=0...(ii)\*x^2+y^2+2y-3=0....(iii)\*using;.....(i);and;.....(ii)\*Rightarrow 1+2x-3=0Rightarrow x=1\*Now,;using;...(i); and;...(iii)\*Rightarrow 1+3y-3=0Rightarrow y=1\* herefore center ;of;the;such;circle;is;(1,1)\*

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Deependra Verma

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