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  • Find the distance from the centre at which the velocity in s.h.m will be half of the maximum.

Find the distance from the centre at which the velocity in s.h.m will be half of the maximum.

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eginarrayl extWe know that,\ extspeed in S.H.M,\ v=omegasqrta^2-x^2\ v_max=aomega\ extGiven in question,\ v=fracv_max2=omegasqrta^2-x^2\ Rightarrowfracaomega2=omegasqrta^2-x^2\ Rightarrow x^2=a^2-fraca^24\ Rightarrow x=fracsqrt32a\ extAt, x=fracsqrt32a, extspeed is half of its maximum. endarray

Posted by

Deependra Verma

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The velocity in a S H M at the amplitude is

 

Posted by

Surjeet Kumar suman

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