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Find the probability distribution of X, the number of heads in a simultaneous toss of two coins.

 

 

 

 

 
 
 
 
 

Answers (1)

S=\left \{HH,TH,HT,TT}{ \right \}                  x(HH)=2

x\Rightarrow no.\: \: of\: \: heads                               x(TH)=1

                                                                       x(HT)=1

                                                                       x(TT)=0

x 0 1 2
P(x) \frac{1}{4} \frac{2}{4} \frac{1}{4}

 

Posted by

Ravindra Pindel

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