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Find the total extension of a solid bar oflength 500mm and 50 mm Diameter withCentral anis tensile force of 400 KN - AssumeE = 200 GPa .​

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\delta=(P l) /(A E)

\\ $P=$ Force \ applied \ on \ the \ object \ $=400 KN =4 \times 10^{5} N$ (given) \\ \\ $I =$ Length \ of \ the \ solid \ bar \ $=500 mm =0.5 m$ (given)\\ \\ $A =$ Area \ of\ the \ solid \ bar \ $=0.012 m ^{2}$ (given)\ \\\\ $E =$ Young's \ modulus \ of \ the \ solid \ bar\ $=200 GPa =2 \times 10^{11}( given )$

\begin{array}{l} \delta=\left(4 \times 10^{5} \times 0.5\right) /\left(0.012 \times 2 \times 10^{11}\right) \\ \delta=\left(2 \times 10^{5}\right) /\left(1 \times 10^{11}\right) \\ \therefore \delta=2 \times 10^{-6} \end{array}

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Deependra Verma

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