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  • If A = (6i-8j) units, B = (-8i-3j) units, and C = (26i-19j) units, find b ans a such that aA + bB + C = 0

If A = (6i-8j) units, B = (-8i-3j) units, and C = (26i-19j) units, find b ans a such that aA + bB + C = 0

Answers (1)

aA=6ai-8aj

bB=-8bi-3bj

C=26i-19j

Given aA+bB+C=0i+0j

(6a-8b+26)i-(8a+3b+19)j=0i+0j

comparing coefficient of i and j

6a-8b=-26

2a-4b=-13.....(1)

8a+3b=-19......(2)

making the coefficient of a similar

8a-16b=-52....(3)

8a+3b=-19....(4)

equation 4-3 implies

19b=33

b=33/19

from (1)

2a=-13+4(33/19)

2a=-115/19

a=-115/38

 

Posted by

Safeer PP

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