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If omega be a cube root of unity and (1+omega^2)^n=(1+omega^4)^n then the least +ve value of n is

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Solution: We know that , $1+omega +omega ^2=0$ & $omega ^3=1$

Now , $(1+omega -omega ^2)^7=(-omega ^2-omega ^2)^7=(-2omega ^2)^7=-128omega ^2$

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Deependra Verma

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