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  • If one root of the equation x^2+px+8=0 is 4 while the equationx^2+px+p=0 has equal roots , then the value of q

If one root of the equation x^2+px+8=0 is 4 while the equationx^2+px+p=0 has equal roots , then the value of q

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Solution:

\ x^2+px+8=0; put ;x=4\ \Rightarrow 16+4p+8=0\ \Rightarrow p=-6

For the second equation \D=0

\D=0\ \Rightarrow 36-4q=0\ \Rightarrow q=9

Posted by

Deependra Verma

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