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If sin theta +cos theta =a then sin^3 theta +cos^3 theta=?

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Solution: We have , $sin heta +cos heta =a$

$Rightarrow$ $sin^3 heta+cos^3 heta=(sin heta+cos heta)(sin^2 heta+cos^2 heta-sin heta cos heta)$

$sin^3 heta+cos^3 heta=a(1-cos hetasin heta)=a[1-fraca^2-12]=fraca2(3-a^2)$

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Deependra Verma

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