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  • It the 10th term of an AP is 47 and its first term is 2,find the sum of its first 15 term

It the 10th term of an AP is 47 and its first term is 2,find the sum of its first 15 term

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best_answer

a = 2

a = first term, d = common difference

10th term of AP = a+9d = 47 = 2+9d = 47

9d=45

d=5

sum of 15 term = 15/2(2x2+(15-1)5) = 555

Posted by

himanshu.meshram

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