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Please Solve RD Sharma Class 12 Chapter Relation Exercise 1.2 Question 10 Maths Textbook Solution.

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Answer: R is an equivalence relation. 
The set of all elements in A related to triangle T is the set of all triangles.
Hint: To prove equivalence relation it is necessary that the given relation should be reflexive, symmetric and transitive.
Given: \! R= \left \{ \left ( P_{1}, P_{2}\right ):P_{1}\, and\, P_{2} \: have\: same\: number\: o\! f\: sides \right \}
Explanation:
Reflexive:
R\: is\: re\! f\! lexive\: \text{ since } (P_{1}, P_{1})\epsilon \: R \: \text{ is }\: the\: same \: polygon\: as\: itsel\! f.
Symmetric:
Let (P_{1}, P_{2}) \epsilon \: R
P_{1}\, \text{ and }\, P_{2}\: have \: the \: same\: numbers\: o\! f\: sides.
P_{2}\, \text{ and }\, P_{1} \: \text{ have }\: the\: same \: number \: o\! f \: side.
(P_{2}, P_{1}) \epsilon \: R
R is symmetric
Transitive:
Let\:\left ( P_{1}, P_{2} \right ) , (P_{2}, P_{3})\: \epsilon \: R
P_{1} \text{ and } P_{2}\: have \: the\: same\: number \: o\! f \: sides
Also\: P_{2}\, and\, P_{3}\: have\: the\: same\: number\: o\! f\: sides.
P_{1}\, and\, P_{3} \: have \: the\: same\: number\: o\! f \: sides.
(P_{1}, P_{3}) \: \epsilon \: R
R is transitive.
Therefore, R is reflexive, symmetric and transitive.
Hence, R is an equivalence relation.
The elements in A related to the right-angle triangle (T) with sides 3, 4, and 5 are those polygons that have 3 sides (since T is a polygon with 3 sides).
Hence, the set of all elements in A related to triangle T is the set of all triangles.

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