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Provide RD Sharma solution for Maths Class 12 Chapter 5 Determinants Exercise Very short question Question 2 for maths textbook solution.

Answers (1)

Answer : x=3

Hint: Here we use basic concept of singular matrix

Given : \left|\begin{array}{cc} 5-x & x+1 \\ 2 & 4 \end{array}\right|

Solution :

Let this matrix is singular So,
it's determinant should be zero

So now, \left|\begin{array}{cc} 5-x & x+1 \\ 2 & 4 \end{array}\right|=0

\begin{aligned} &(5-x)(4)-2(x+1)=0 \\ &20-4 x-[2 x+2]=0 \\ &20-4 x-2 x-2=0 \\ &18-6 x=0 \end{aligned}

So,

x=\frac{18}{6}=3
 

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