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Provide solution for RD Sharma maths Class 12 Chapter 5 Determinants Exercise VSQ Question 27 maths textbook solution.

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Answer: 0

Hint: Here we use basic concept of determinant of matrix

Given:  \left|\begin{array}{ccc} 2 & -3 & 5 \\ 4 & -6 & 10 \\ 6 & -9 & 15 \end{array}\right|

Solution :

\rightarrow Using column operation, \mathrm{C}_{2} \rightarrow C_{2}+C_{3}

We get,

\Delta=\left|\begin{array}{ccc} 2 & -3+5 & 5 \\ 4 & -6+10 & 10 \\ 6 & -9+15 & 15 \end{array}\right|

\Delta=\left|\begin{array}{ccc} 2 & 2 & 5 \\ 4 & 4 & 10 \\ 6 & 6 & 15 \end{array}\right|

\rightarrowHere 1st and 2nd column are similar
\rightarrowAccording to determinant if two or more columns are similar
It's determinant must be zero

So \Delta = 0

 

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