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The centripetal force acting on a body of mass 500g is 10*10^-2N if the radius of the path is 10m calculate the velocity with which the body moves

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Centripetal \ force\ $F=m v^{2} / r$\\ $\mathrm{F}=10^{*} 10^{-2}=0.1 \mathrm{N}$\\ $\mathrm{m}=500 \mathrm{g}=1 / 2=0.5 \mathrm{Kg}$\\ $r=10 \mathrm{m}$\\ $0.1=0.5 v^{2} / 10$\\ $v^{2}=2$\\ $\mathrm{v}=\sqrt{2} \mathrm{m} / \mathrm{sec}$

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