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The difference between the squares of two consecutive odd integers is always divisible which which one digit number?Id be thankful for explanation as well.

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Let;the;two;consecutive;odd;integers;be;(2n+1);and;(2n+3).;Then, \*Rightarrow (2n+3)^2-(2n-1)^2=(2n+3+2n+1)(2n+3-2n-1)\*Rightarrow (4n+4)	imes2=8(n+1)\*which ;is ;divisible; by; 8.

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Deependra Verma

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