Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • The eccentric angle in the first quadrant of a point on the ellipse x^2/10 +y^2/8=1 at a distance of 3 units from the centre of the ellipse is

The eccentric angle in the first quadrant of a point on the ellipse x^2/10 +y^2/8=1 at a distance of 3 units from the centre of the ellipse is

Answers (1)

best_answer

Solution:

\ a=sqrt10;b=sqrt8

Let a point \ P(sqrt10cos heta ,sqrt8sin heta ) .its distance from (0,0) is 3.

\ Rightarrow 10cos^2 heta +8sin^2 heta =9\ \Rightarrow 2cos^2 heta =1\ \Rightarrow cos heta =1/sqrt2\ \Rightarrow heta =pi /4

Posted by

Deependra Verma

View full answer

Similar Questions

Latest Question