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  • The equation of the directix of the parabola y^2+4y+4x+2=0 is

The equation of the directix of the parabola y^2+4y+4x+2=0 is

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Solution: we have the given equation \ y^2+4y+4x+2=0

The given equation can be written as 

\ (y+2)^2=-4(x-1/2)

Form \ Y^2=4AX; where ; 4A=-4Rightarrow A=-1

The directrix is \ X=-A; or; (x-1/2)=-(-1)\ \Rightarrow x=3/2

Posted by

Deependra Verma

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