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The integral value of m for which the Quadratic equation (x+m)(x-5)+1=0 has integral roots ,are

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Solution: The given equation can be written as:

\ x^2+(m-5)x+(1-5m)=0 ........(1)\ \ Rightarrow D=0

gives \ m=-3 ; and; m=-7

Now, \ x=1/2	imes (5-m)

for     m=-3 ,x=4

for m=-7 , x=6

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Deependra Verma

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