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The number of real roots of the equation (x-1)^2+(x-2)^2+(x-3)^2=0

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Solution: $\X^2+Y^2+Z^2=0Rightarrow X=Y=Z=0$

This gives x=1, x=2 and x=3 but these values do not satisfy the given equation.

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Deependra Verma

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