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  • The probability of selecting a blue marble at random from a jar that contains only blue, black and green marbles is . The probability of s

The probability of selecting a blue marble at random from a jar that contains only blue, black and green marbles is \frac{1}{5}. The probability of selecting a black marble at random from the same jar is \frac{1}{4}. If the jar contains 11 green marbles, find the total number of marbles in the jar.

 

 
 
 
 
 

Answers (1)

Given in the question

\text{P(Blue Marble)} = \frac{1}{5}

\text{P(Black Marble)} = \frac{1}{4}

\begin{align*} \text{P(Green Marble)} &= 1 - \left(\frac{1}{5} + \frac{1}{4}\right) \\ & = 1 - \left(\frac{9}{20} \right )\\ & = \frac{11}{20} \end{align*}

Jar contains 11 green marbles (given)

Let total no. of marbles be x.

Then

 \frac{11}{20}\times x = 11

    \Rightarrow x = 20

Total no. of marbles in the jar = 20.

Posted by

Safeer PP

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