Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • The random variable X has a probability distribution P(X) of the following form, where ‘k’ is some number.  <img alt="P(X=x)=\begin{cases}k,&i\!f\: \: x=0\\ 2k,&i\!f\: \: x=1\\ 3k,&i\!f\: \: x=3\\0,&otherwise

The random variable X has a probability distribution P(X) of the following form, where ‘k’ is some number. 

P(X=x)=\begin{cases}k,&i\!f\: \: x=0\\ 2k,&i\!f\: \: x=1\\ 3k,&i\!f\: \: x=3\\0,&otherwise \end{cases}

Determine the value of ‘k’. 

 

 

 

 
 
 
 
 

Answers (1)

As we know sum of all probablities in a probablity distribution is 1.

i.e   \sum p=1

\therefore k+2k+3k+0=1

\Rightarrow 6k=1

\Rightarrow k=\frac{1}{6}

Which is the required value

 

Posted by

Ravindra Pindel

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE practical exams 2026 will be cancelled over non-compliance with guidelines, says board

Latest Question