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What is electrical resistivity? Derive its SI unit. In a series of an electrical circuit comprising a resistor made up of a metallic wire, the ammeter reads 100 mA. If the length of the wire is doubled, how will the current in the circuit change? Justify your answer.

 

 

 

 
 
 
 
 

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Electrical Resistivity (or resistivity) is a property of the material of a conductor is the resistance offered by the conductor of unit length with the unit cross-sectional area.

            \rho = \frac{RA}{l}    Here R is resistance

                                            A is the area of cross-section

                                            l is the length of wire

                                           \rho is the resistivity

Unit of \begin{align*} \rho &= \frac{\text{Ohm metre}^2}{\text{metre}} \\ & = \text{Ohm metre}\end{align*}

SI unit of restiivity is \Omega \ m \ (\text{Ohm Metre})

We know that     

                        R = \frac{\rho l}{A}

                        R \propto l

If the length of the wire is doubled then the resistance of the conductor also doubles. So, the current is reduced to half

                        I\propto \frac{1}{R}

\therefore Ammetre reading = \frac{100mA}{2} = 50mA

 

Posted by

Sumit Saini

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