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  • Explain solution RD Sharma class 12 Chapter 27 Striaght Line in Space Exercise Very Short Answer question 18

Explain solution RD Sharma class 12 Chapter 27 Striaght Line in Space Exercise Very Short Answer question 18

Answers (1)

Answer:

Required answer is   \frac{-1}{\sqrt{6}}, \frac{1}{\sqrt{6}}, \frac{2}{\sqrt{6}}

Hint:

Use the equation of a line in space.

Given:

\frac{4-x}{3}=\frac{y+3}{3}=\frac{z+2}{6}

Solution:

We have,

\frac{4-x}{3}=\frac{y+3}{3}=\frac{z+2}{6}

The equation of the given line can be rewritten as,

\frac{x-4}{-3}=\frac{y+3}{3}=\frac{z+2}{6}

The direction ratios of the line parallel to the given line are proportional to  -3,3,6

The direction cosines of the line parallel to the given line are proportional to

\begin{aligned} &\frac{-3}{\sqrt{(-3)^{2}+3^{2}+6^{2}}}, \frac{3}{\sqrt{(-3)^{2}+3^{2}+6^{2}}}, \frac{6}{\sqrt{(-3)^{2}+3^{2}+6^{2}}} \\ & \end{aligned}

=\frac{-1}{\sqrt{6}}, \frac{1}{\sqrt{6}}, \frac{2}{\sqrt{6}}

Posted by

infoexpert27

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