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  • Please Solve RD Sharma Class 12 Chapter 27 Straight Line in Space Exercise Fill in the blanks Question 2 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter 27 Straight Line in Space Exercise Fill in the blanks Question 2 Maths Textbook Solution.

Answers (1)

Answer :  (5 \hat{\imath}-4 \hat{\jmath}+6 \hat{k})+\lambda(-3 \hat{\imath}+7 \hat{\jmath}+2 \hat{k})

Hint : Compare the equation with the formula

Given :    \frac{5-x}{3}=\frac{y+4}{7}=\frac{z-6}{2}   

Solution :    We have given line as

                     \frac{x-5}{-3}=\frac{y+4}{7}=\frac{z-6}{2}

                      By comparing with equation

                      \frac{x-x_{1}}{a}=\frac{y-y_{1}}{b}=\frac{z-z_{1}}{c}

                    The given line passes through the point (x1 , x2, x3)

                    i.e. (5 , -4 , 6) and direction ratios are (a ,b ,c) i.e. (-3 , 7 ,2)

                    Now , we can write vector equation of the line as

                    \vec{A}=(5 \hat{\imath}-4 \hat{\jmath}+6 \hat{k})+\lambda(-3 \hat{\imath}+7 \hat{\jmath}+2 \hat{k}

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