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Please solve RD Sharma class 12 chapter 27 Straight Line in Space exercise Multiple choice question 13 maths textbook solution

Answers (1)

Answer: Correct answer is D

Hint: The given line is parallel to the vectors

Given: \frac{x-3}{3}=\frac{y-2}{1}=\frac{z-1}{0}

Solution: Given the equation is

\frac{x-3}{3}=\frac{y-2}{1}=\frac{z-1}{0}

 Also the given line is parallel to the vector,

\overrightarrow{b_{1}}=3 \hat{\imath}-\hat{\jmath}+0 \hat{k}

Let  x \hat{\imath}+y \hat{\jmath}+z \hat{k} be perpendicular to the given line.

Now, 

3x+4y+Oz=0

it is satisfied by the coordinates of z- axis, i.e, (0,0,1)

Hence, the given line is perpendicular to z – axis

So, the correct option is (d)

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