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  • Please solve RD Sharma class 12 chapter 27 Straight Line in Space exercise Multiple choice question 13 maths textbook solution

Please solve RD Sharma class 12 chapter 27 Straight Line in Space exercise Multiple choice question 13 maths textbook solution

Answers (1)

best_answer

Answer: Correct answer is D

Hint: The given line is parallel to the vectors

Given: \frac{x-3}{3}=\frac{y-2}{1}=\frac{z-1}{0}

Solution: Given the equation is

\frac{x-3}{3}=\frac{y-2}{1}=\frac{z-1}{0}

 Also the given line is parallel to the vector,

\overrightarrow{b_{1}}=3 \hat{\imath}-\hat{\jmath}+0 \hat{k}

Let  x \hat{\imath}+y \hat{\jmath}+z \hat{k} be perpendicular to the given line.

Now, 

3x+4y+Oz=0

it is satisfied by the coordinates of z- axis, i.e, (0,0,1)

Hence, the given line is perpendicular to z – axis

So, the correct option is (d)

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