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  • Please Solve RD Sharma Class 12 Chapter 27 Straight Line in Space Exercise Very Short Answer Question 2 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter 27 Straight Line in Space Exercise Very Short Answer Question 2 Maths Textbook Solution.

Answers (1)

Answer:

Required answer is  \lambda \hat{j}

Hint:

Use properties of vector

Given:

Cartesian and vector equation of y-axis

Solution:

Since y-axis passes through the point  \left ( 0,0,0 \right )   having position vector

\vec{a}=0 \hat{i}+0 \hat{j}+0 \hat{k}   and is parallel to the vector  \vec{b}=0 \hat{i}+1 \hat{j}+0 \hat{k}   having direction ratios proportional to 0, 1, 0

The Cartesian equation of y-axis is

\begin{aligned} &\frac{x-0}{0}=\frac{y-0}{1}=\frac{z-0}{0} \\ & \end{aligned}

\frac{x}{0}=\frac{y}{1}=\frac{z}{0}

Also the vector equation is

\begin{aligned} &\vec{r}=\vec{a}+\lambda \vec{b} \\ \end{aligned}

=0 \hat{i}+0 \hat{j}+0 \hat{k}+\lambda(0 \hat{i}+\hat{j}+0 \hat{k}) \\

=\lambda \hat{j}

Posted by

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